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Today at 3:17 PM
Mathematics

Answered

Rewrite with only sin x and cos x. Sin2x-cos2x

Answer :

sbcardinals sbcardinals

Today at 3:21 PM

From trig identities, we know that sin2x = 2sinxcosx and cos2x = [tex]cos^{2} x - sin^{2} x[/tex]

So sin2x-cos2x = 2sinxcosx - ([tex]cos^{2} x - sin^{2} x[/tex]) in terms of sinx and cosx

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