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Calculate the mass in grams of hydrogen chloride produced when 5.15 l of molecular hydrogen measured at stp reacts with an excess of molecular chlorine gas. h2(g) + cl2(g) → 2hcl(g)

Answer :

Edufirst

Answer: 17.9 g


Explanation:


1) Chemical equation:


H₂ (g) + Cl₂ (g) → 2HCl (g)


2) mole ratios:


1 mol H₂ : 1 mol Cl₂ : 2 mol HCl


3) Since, the pressure and temperature conditions do not change, the same proportion is valid for the volumes. Then:


1 liter H₂ / 2 liter HCl = 5.15 liter H₂ / x


⇒ x = 5.5 × 2 / 1 = 11 liter HCl


4) Calculate the number of moles of HCl in 11 liter of HCl at STP


At STP, 1 mol of gas = 22.4 liter


⇒ 11 liter × 1mol / 22.4 liter = 0.491 mol HCl


5) Use the molar mass to convert 0.491 mol to grams


molar mass of HCl = 1.008 g/mol + 35.453 g/mol = 36.461 g/mol


mass in grams = nuumber of moles × molar mass = 36.461 g/mol × 0.491 mol = 17.90 g.



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