Given:
1.0 mol of CaO
Required:
grams of water
Solution:
CaO + H2O → Ca(OH)2
Molar mass of H2O = 18.02g H2O
1mol CaO(1 mol H2O/1 mol CaO)(18.02g H2O/1 mol H2O) = 0.055g H2O
Answer: The mass of water required will be 18 grams.
Explanation:
For the given chemical reaction:
[tex]CaO+H_2O\rightarrow Ca(OH)_2[/tex]
By Stoichiometry of the reaction:
1 mole of calcium oxide reacts with 1 mole of water.
So, 1 mole of calcium oxide will react with = [tex]\frac{1}{1}\times 1=1[/tex] mole of water.
To calculate the mass of water required, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]
We are given:
Moles of water = 1 mole
Molar mass of water = 18 g/mol
Putting values in above equation, we get:
[tex]1mol=\frac{\text{Mass of }H_2O}{18g/mol}\\\\\text{Mass of }H_2O=18g[/tex]
Hence, the mass of water required will be 18 grams.
