Answer :

JDcap

Answer:

[tex]\boxed{t=15}[/tex]

Step-by-step explanation:

Function: [tex]f(t)=2^{t/3}[/tex]

You need to replace f(t) for 32 and isolate "t", like this:

[tex]f(t)=2^{t/3}\\ 32=2^{t/3}\\ 2^5=2^{t/3}[/tex]

Since both bases are 2, we only take the powers:

[tex]5=\dfrac{t}{3}\;\Longrightarrow 5\cdot3=t=15[/tex]

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