Answer :
The oxidation state of Na decreases from 1 to 0 in this reaction Li (s) + NaOH (aq) → LiOH(aq) + Na(s).
What is Oxidation state ?
Oxidation state is also called Oxidation number is defined as the number assigned to atoms in molecules to represent the general distribution of electrons.
What is a Chemical Reaction ?
A chemical reaction is a process in which chemical bonds between atoms to break and reorganize, to form other new substances.
The given chemical reaction is
Li (s) + NaOH (aq) → LiOH(aq) + Na(s)
The oxidation state of Li is zero in the reactant side. The oxidation state of Na in the reactant side is 1. The oxidation state of Li in the product side is 1. The oxidation state of Na in reactant side is 0.
So the oxidation number of Na decreases from 1 to 0.
Thus from the above conclusion we can ay that The oxidation state of Na decreases from 1 to 0 in this reaction Li (s) + NaOH (aq) → LiOH(aq) + Na(s).
Learn more about the Oxidation State here: https://brainly.com/question/8990767
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