Answer :
Answer:
The magnetic field in the center of the solenoid is [tex]7.8\times10^{-3}\ T[/tex].
Explanation:
Given that,
Length of solenoid = 0.425 m
Number of turns N = 950
Current I = 2.75 A
The magnetic field in the center of the solenoid is the product of the current , number of turns per unit length and permeability.
In mathematical form,
[tex]B = \mu_{0}nI[/tex]
Where, [tex]n = \dfrac{N}{l}[/tex]
N = number of turns
L = length
I = current
Now, The magnetic field
[tex]B = \dfrac{\mu_{0}NI}{l}[/tex]
Put the value into the formula
[tex]B=\dfrac{4\pi\times10^{-7}\times950\times2.75}{0.425}[/tex]
[tex]B=\dfrac{4\times3.14\times10^{-7}\times950\times2.75}{0.425}[/tex]
[tex]B=7.8\times10^{-3}\ T[/tex]
Hence, The magnetic field in the center of the solenoid is [tex]7.8\times10^{-3}\ T[/tex].