Answer :
Answer:
t = 206 sec
Explanation:
m = mass of the ocean liner = 39000 Mg = 39000 x 10⁶ g = 3.9 x 10⁷ kg
F = constant force applied by the tugboat = 210 kN = 210000 N
v₀ = initial velocity of the liner = 4 km/h = 1.11 m/s
v = final velocity of the liner = 0 m/s
a = acceleration of the liner
Acceleration of the liner is given as
[tex]a = - \frac{F}{m}[/tex]
[tex]a = - \frac{210000}{3.9\times 10^{7}}[/tex]
a = - 0.0054 m/s²
Using the equation
v = v₀ + at
0 = 1.11 + (- 0.0054) t
t = 206 sec