Answer :
Answer:
0.1 nm
Explanation:
Potential difference of the electron = 150 V
Mass of electron [tex]m=9.1\times 10^{-31}kg[/tex]
Charge on electron [tex]1.6\times 10^{-19}C[/tex]
Plank's constant [tex]h=6.67\times 10^{-34}[/tex]
If the velocity of the electron is v
Then according to energy conservation [tex]eV =\frac{1}{2}mv^2[/tex]
[tex]v=\sqrt{\frac{2eV}{m}}=\sqrt{\frac{2\times 1.6\times 10^{-`19}\times 150}{9.1\times 10^{-31}}}=7.2627\times 10^{6}m/sec[/tex]
According to De Broglie [tex]\lambda =\frac{h}{mv}=\frac{6.67\times 10^{-34}}{9.1\times 10^{-31}\times 7.2627\times 10^{6}}=0.1nm[/tex]