Answer :
Answer:
-1.19 m
Explanation:
R1 = + 4 cm
R2 = - 15 cm
n = 1.5
distance of object, u = - 1 m
let the focal length of the lens is f and the distance of image is v.
use lens makers formula to find the focal length of the lens
[tex]\frac{1}{f}=\left ( n-1 \right )\left ( \frac{1}{R_{1}}-\frac{1}{R_{2}} \right )[/tex]
By substituting the values, we get
[tex]\frac{1}{f}=\left ( 1.5-1 \right )\left ( \frac{1}{4}+\frac{1}{15} \right )[/tex]
[tex]\frac{1}{f}=\frac{19}{120}[/tex] .... (1)
By using the lens equation
[tex]\frac{1}{f}=\frac{1}{v}-\frac{1}{u}[/tex]
[tex]\frac{19}{120}=\frac{1}{v}+\frac{1}{1}[/tex] from equation (1)
[tex]\frac{1}{v}=\frac{19-120}{120}[/tex]
v = -1.19 m