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A survey of athletes at a high school is conducted, and the following facts are discovered: 33% of the athletes are football players, 66% are basketball players, and 20% of the athletes play both football and basketball. An athlete is chosen at random from the high school: what is the probability that the athlete is either a football player or a basketball player?

Answer :

Answer:

99%.

Step-by-step explanation:

Givens

  • 33% of the athletes are football players.
  • 66% are basketball players.
  • 20% of the athletes play both football and basketball.

Now, these percentages are representations regarding the total number of students.

It's important to know that percentages can also represents probabilities, like in this case.

So, basically, there's 33% to chose a football player, there's 66% to choce a basetball player, and there's 20% to choce a student who plays both football and basketball.

Now, if we want to know the probability of choosing someone who plays either football or baskebatll, then we must sum 33% + 66% = 99%.

Therefore, the probability is 99% of picking a student who plays either football or basketball.

abiolataiwo2015

The probability that the athlete is either a football player or a basketball player is 79%

Football players=33%

Basketball players=66%

Both football and basketball=20%

Probability=Football players + Basketball players

- Both football and basketball

Probability= 33% + 66% - 20%

Probability=79%

Inconclusion The probability that the athlete is either a football player or a basketball player is 79%

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https://brainly.com/question/18263724

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