Answered

A body moving with uniform acceleration has

a velocity of 11.1 cm/s when its x coordinate

is 3.59 cm.

If its x coordinate 2.48 s later is −3.58 cm,

what is the x-component of its acceleration?

Answer in units of cm/s

.

Answer :

skyluke89

The x-component of the acceleration is [tex]-11.3 cm/s^2[/tex]

Explanation:

This problem is an example of uniformly accelerated motion, so we can solve it by using the following suvat equation:

[tex]s=ut+\frac{1}{2}at^2[/tex]

where

u is the initial velocity

a is the acceleration

s is the displacement

t is the time

For the body in this problem, we have:

u = 11.1 cm/s is the initial velocity

The displacement is

s = -3.58 - (3.59) = -7.17 cm

While the time is

t = 2.48 s

Substituting and solving the formula for a, we find the x-component of the acceleration:

[tex]a=\frac{2s}{t^2}-\frac{2u}{t}=\frac{2(-7.17)}{(2.48)^2}-\frac{2(11.1)}{2.48}=-11.3 cm/s^2[/tex]

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