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the path if an arrow released from a bow can be modeled by y=-0.04 x squared +4x + 3 where x is the horizontal distance (in feet) and y is the vertical distance in feet find and interpret the coordinates of the vertex

Answer :

valenbraca

Answer:

The vertex is at the point (50,103). The arrow will reach the highest point 50 feet horizontal distance and 103 feet vertical distance from where it was launched.

Step-by-step explanation:

The equation of a parabola is given by:

[tex]y=ax^2+bx+c[/tex]

The vertex is the maximum or minimum value of the parabola  

In this case, we have the following parabola:

[tex]y=-0.04 x^2+4x + 3[/tex]

where

a=-0.04

b=4

c=3

The x-coordinate of the vertex can be found by the formula:

[tex]x=\frac{-b}{2a}[/tex]

Then, we find the x-coordinate by replacing the values of a nd b:

[tex] x=\frac{-b}{2a} \\ x=\frac{-(4)}{2\times (-0.04)} \\ x=50[/tex]

Next, we replace the value of x in the parabola equation:

[tex]y=-0.04 x^2+4x + 3 \\ y =-0.04\times 50^2+4\times 50 + 3 \\ y =-100+200+ 3 \\ y=103[/tex]

The vertex is at the point (50,103)

${teks-lihat-gambar} valenbraca

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