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A train moving with an initial velocity of 20 m/s accelerated at 4 m/s^2 for 10 seconds. During this time, the train moves a distance of how many meters

Answer :

MathPhys

Answer:

400 m

Explanation:

Given:

v₀ = 20 m/s

a = 4 m/s²

t = 10 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (20 m/s) (10 s) + ½ (4 m/s²) (10 s)²

Δx = 400 m

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