Answer :
Answer: The mass of magnesium in given amount of alloy is 0.396 g
Explanation:
We are given:
Percent mass of manganese = 4.5 %
Percent mass of copper = 3.5 %
Percent mass of magnesium = 0.45 %
Percent mass of aluminium = (100 - 4.5 - 3.5 - 0.45) = 91.55 %
Mass of alloy = 88 g
We need to calculate the mass of magnesium in 88 g of alloy, we get:
[tex]\Rightarrow 88\times \frac{0.45}{100}=0.396g[/tex]
Hence, the mass of magnesium in given amount of alloy is 0.396 g
The amount of magnesium that is present in a 88 g sample of duralin is 0.396 grams.
Given the following data:
- Percentage by mass of manganese = 4.5%
- Percentage by mass of copper = 3.5%
- Percentage by mass of magnesium = 0.45%
- Mass of duralin = 88 grams
To determine the amount of magnesium that is present in a 88 g sample of duralin:
In this exercise, you're required to calculate the total amount of magnesium that is present in duralin, if it takes 0.45 percent of the total mass of duralin.
[tex]Mass\;of\;magnesium = \frac{0.45}{100} \times 88\\\\Mass\;of\;magnesium = \frac{39.6}{100}[/tex]
Mass of magnesium = 0.396 grams
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