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A glider of mass 5.0 kg hits the end of a horizontal rail and bounces off with the same speed, in the opposite direction. The collision is elastic and takes place in a time interval of 0.2s, with an average force of 100N. What was the speed, in m/s, of the glider?A glider of mass 5.0 kg hits the end of a horizontal rail and bounces off with the same speed, in the opposite direction. The collision is elastic and takes place in a time interval of 0.2s, with an average force of 100N. What was the speed, in m/s, of the glider?

Answer :

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To develop this problem it is necessary to apply the equations concerning the conservation of the moment.

By definition the moment can be expressed in two ways,

The first as a function of force and because of time, that is

[tex]\Delta P = F \Delta t[/tex]

And also based on mass and speed

[tex]\Delta P = m_2v_2-m_1v_1[/tex]

Speed 1 is moving in the opposite direction to our reference system and it remains constant, as is the mass therefore

[tex]\Delta P = mv-(-mv)[/tex]

[tex]\Delta P = 2mv[/tex]

Equation both expression we have that,

[tex]2mv = F\Delta t[/tex]

[tex]v = \frac{F\Delta t}{2m}[/tex]

[tex]v = \frac{100*0.2}{2(5)}[/tex]

[tex]v = 2m/s[/tex]

Therefore the speed of the glider is 2m/s

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