Answer :

Answer:

[tex]y=3(2)^{x}[/tex]

Step-by-step explanation:

Given.

Two points are given.

[tex](x, y)=(-1,\frac{3}{2})[/tex] and [tex](x, y)=(3,24)[/tex]

An exponential function is in the general form.

[tex]y=a(b)^{x}[/tex]-------(1)

We know the points  [tex](-1,\frac{3}{2})[/tex] and [tex](3,24)[/tex]

put the first point value in equation 1

[tex]\frac{3}{2}=a(b)^{-1}[/tex]

[tex]\frac{3}{2}=\frac{a}{b}[/tex]

[tex]a=\frac{3}{2}\times b[/tex]--------(2)

put the second point value in equation 1

[tex]24=a(b)^{3}[/tex]----------(3)

Put the a value from equation 2 to equation 3

[tex]24=\frac{3}{2}\times b(b)^{3}[/tex]

[tex]b^{3+1}=\frac{24\times 2}{3}[/tex]

[tex]b^{4} = 16\\b=\sqrt[4]{16} \\b=2[/tex]

Put the b value in equation 2

[tex]a=\frac{3}{2}\times 2[/tex]

[tex]a=3[/tex]

Put the a and b value in equation 1

[tex]y=3(2)^{x}[/tex]

So, the exponential function that passes through the points  [tex](-1,\frac{3}{2})[/tex] and [tex](3,24))[/tex] are [tex]y=3(2)^{x}[/tex].

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