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Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated NaOH ( aq ) . Calculate the amount of Ga ( s ) that can be deposited from a Ga ( III ) solution using a current of 0.520 A that flows for 20.0 min .

Answer :

dsdrajlin

Answer:

0.150 g

Explanation:

First, we will write the reduction half-reaction to produce Ga(s)

Ga³⁺(aq) + 3 e⁻ → Ga(s)

We can establish the following relations:

  • 1 min = 60 s
  • 1 A = 1 c/s
  • 1 mole of e⁻ has a charge of 96468 c (Faraday's constant)
  • 1 mole of  Gas(s) is deposited when 3 moles of e⁻ circulate.
  • The molar mass of Ga is 69.72 g/mole.

The mass of Ga(s) deposited when a current of 0.520 A flows for 20.0 min is:

[tex]20.0min.\frac{60s}{1min} .\frac{0.520c}{s} .\frac{1mol/e^{-} }{96468c} .\frac{1molGa}{3mol/e^{-}} .\frac{69.72gGa}{1molGa} =0.150gGa[/tex]

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