Answered

What is the distance (in meters) of an object that has an angular diameter of 100 arcseconds and a linear diameter of 50 meters?

Answer :

opudodennis

Answer:

0.02424 m

Explanation:

Using the formula

[tex]L=2a\frac {tan \theta}{2}[/tex] and substituting [tex]\frac {100}{3600}[/tex] for [tex]\theta[/tex], 50 m for a then

[tex]L=2\times50\times tan (\frac {100}{2\times 3600})=0.02424 m[/tex]

Therefore, the distance in metres is 0.02424 m

The angular diameter of a thing is the diameter which is made by due to seen by a observer in the space.

The distance of the object is 2.796 meters.

What is angular diameter?

The angular diameter of a thing is the diameter which is made by due to seen by a observer in the space.

The relation between the angular diameter and linear diameter is that the angular diameter is proportional ratio of the linear diameter of the object to the distance.

The relation between the angular diameter and linear diameter can be given as,

[tex]d=2a\times\tan\dfrac{\theta}{2}[/tex]

Here [tex]\theta[/tex] is the  angular diameter, [tex]a[/tex] is the linear diameter and [tex]d[/tex] is the distance of the object.

Given information-

Angular diameter of the object is 100 arc seconds.

Linear diameter of the object is 50 meters.

Convert angular diameter in degrees,

[tex]a=100\times\dfrac{100}{3600}\\a=\dfrac{100}{36}[/tex]

Put the values in the above formula as,

[tex]d=2\times10\times\tan\dfrac{100}{36\times2}\\d=2.796\rm m[/tex]

Hence, the distance of the object is 2.796 meters.

Learn more about the angular diameter here;

https://brainly.com/question/24480408

Other Questions