Answer :
Answer:
see explanation
Step-by-step explanation:
TM = m - t ( m and t are position vectors )
= < - 1, 1, 2 > - < 3, - 5, 6 > ( subtract corresponding components )
= < - 1 - 3, 1 + 5, 2 - 6 >
= < - 4, 6, - 4 >
Given v = < x, y, z > then the magnitude of v is
| v | = [tex]\sqrt{x^2+y^2+z^2}[/tex], thus
| TM | = [tex]\sqrt{(-4)^2+6^2+(-4)^2}[/tex]
= [tex]\sqrt{16+36+16}[/tex] = [tex]\sqrt{68}[/tex] = [tex]\sqrt{4(17)}[/tex] = 2[tex]\sqrt{17}[/tex]
The ordered triple that represents TM is < -4, 6, -4 >
The magnitude of TM is [tex]2\sqrt{17}[/tex].
What does magnitude mean?
Magnitude generally refers to the quantity or distance. In relation to the movement, we can correlate magnitude with the size and speed of the object while traveling. The size of the object or the amount is its magnitude.
TM = m - t ( m and t are positive vector)
= < -1, 1, 2 > - < 3, -5, 6 >
= < -4, 6, -4 >
Given v = < x, y, z > then, the magnitude of v is:
| v | = [tex]\sqrt{x^{2}+y^{2}+z^{2} } \\[/tex]
| TM | = [tex]\sqrt{(-4^{2})+6^{2}+(-4^{2}) } \\[/tex]
[tex]=\sqrt{16+36+16} \\=\sqrt{68} \\=\sqrt{4(17)} \\=2\sqrt{17}[/tex]
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