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An astronomer observes two ordinary stars. The first one turns out to be twice as hot as the second. This means that the first one radiates:O twice as much energy as the second O roughly the same amount of energy as the second O half as much energy as the second O about 16 times the energy of the second O this problem cannot be solved with just the information we were given

Answer :

ricardorrh3

Answer:

About 16 times the energy of the second.

Explanation:

This can be explained thanks to the Stefan-Boltzmann law, which relates temperature directly to the amount of energy released by an object.

With this law in mind, the total energy radiated during 1 second from 1 square meter of any object, equals a constant (5.670374419 × 10−8 watt per meter2 per K4) times the temperature raised to the fourth power.  the equation is:

E = σT4

Since the first star is twice as hot as the second, then the star won't produce twice the energy, but 16 times the energy due to the Stefan-Boltzmann constant. It's also important to know that this law only applies to blackbodies.

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