Answer :
Answer:
0.827 mol
Explanation:
Sodium bicarbonate (NaHCO₃) reacts with hydrochloric acid (HCl) by the equation:
NaHCO₃ + HCl → CO₂ + NaCl + H₂O
Thus, the stoichiometry between sodium bicarbonate and CO₂ is
1 mol : 1 mol.
The molar mass of sodium bicarbonate is 84.007 g/mol, thus the mass in 1 mol is 84.007 g, and the density of it is 2.2 g/mL, thus the volume in 1 mol is:
V = 84.007/2.2 = 38.185 mL
According to Proust's law, the ratio reaction remains constant so:
38.185 mL of NaHCO₃/1 mol of CO₂ = 31.6 mL of NaHCO₃/n
38.185n = 31.6
n = 31.6/38.185
n = 0.827 mol of CO₂