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Assume that a clay model of a lion has a mass of 0.225 kg and travels on the ice at a speed of 0.85 m/s. It hits another clay model, which is initially motionless and has a mass of 0.37 kg. Both being soft clay, they naturally stick together.
What is their final velocity?

Answer :

Answer:

Final velocity will be equal to 0.321 m/sec

Explanation:

We have given mass of clay model of lion [tex]m_1=0.225kg[/tex]

Its speed is 0.85 m/sec, so [tex]v_1=0.85m/sec[/tex]

Mass of another clay model [tex]m_2=0.37kg[/tex]

It is given that second clay is motionless

So its velocity [tex]v_2=0m/sec[/tex]

Now according to conservation of momentum

Momentum before collision will be equal to momentum after collision

So [tex]m_1v_!+m_2v_2=(m_1+m_2)v[/tex], here v is velocity after collision

So [tex]0.225\times 0.85+0.37\times 0+(0.225+0.37)v[/tex]

[tex]0.595v=0.191[/tex]

v = 0.321 m/sec

So final velocity will be equal to 0.321 m/sec  

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