Answer :
Explanation:
The given data is as follows.
Magnetic field strength (B) = 0.65 T
Speed (v) = 2.3 m/s
Induced emf (E) = ?
Formula for emf induced at the ends of the rod of length L which is moving with a speed of v is as follows.
E = BvL
Putting the given values into the formula as follows.
[tex]E_{1} = BvL[/tex]
= [tex]0.65 T \times 2.3 m/s \times L[/tex]
= 1.495 L .............. (1)
When magnetic field is changed to [tex]B_{2}[/tex] = 0.48 T
Now, we assume that the speed be [tex]v_{2}[/tex] to get the emf [tex]E_{2} = E_{1}[/tex].
Then, [tex]0.48 T \times v_{2} \times L = 0.65 T \times 2.3 m/s \times L[/tex]
[tex]v_{2}[/tex] = 3.11 m/s
Therefore, we can conclude that the speed v of the rod be adjusted to reestablish the emf induced between the ends of the rod at its initial value is 3.11 m/s.
The speed of the rod be adjusted to reestablish the EMF induced between the rod's ends at its initial value will be "3.11 m/s"
Magnetic field
According to the question,
Magnetic field strength, B = 0.65 T
Speed, v = 2.3 m/s
Changed magnetic field, B₂ = 0.48 T
We know the relation,
Induced emf, E = BvL
or,
→ E₁ = BvL
By substituting the values,
= 0.65 × 2.3 × L
= 1.495 L
hence,
→ E₁ = E₂
0.48 × v₂ × L = 0.65 × 2.3 × L
v₂ = 3.11 m/s
Thus the above response is correct.
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