Answered

A concrete highway curve of radius 60.0 m is banked at a 19.0 ∘ angle. what is the maximum speed with which a 1400 kg rubber-tired car can take this curve without sliding? (take the static coefficient of friction of rubber on concrete to be 1.0.)

Answer :

Answer:24.26m/s

Explanation:coefficient of static friction is = v^2/rg

1.0=v^2/60*9.81

1.0=v^2=588.6

V^2=588.6

V=24.26m/s

Cricetus

The maximum speed with which a 1400 kg rubber-tired car can take this curve without sliding will be "24.26 m/s".

Friction force

According to the question,

Radius = 60.0 m

Angle = 19.0°

Mass = 1400 kg

Acceleration due to gravity, g = 9.8

We know the formula,

The coefficient of static friction will be:

1.0 = [tex]\frac{v^2}{rg}[/tex]

By substituting the values,

1.0 = [tex]\frac{v^2}{60\times 9.8}[/tex]

1.0 = [tex]\frac{v^2}{588}[/tex]

By applying cross-multiplication, we get

v² = 1.0 × 588

v² = 588

 v = √588

    = 24.26 m/s

Thus the approach above is correct.  

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