Answer :
Answer:
Explanation:
Use the gas equation: PV=nRT
P=pressure
V=Volume
R= gas constant of around 8.31 J/K/mol
T=temperature
n= number of moles
To find n, Rearrange:
n=PV/RT
102kPa= 102,000 kilo pascals which standard form is 102 x 10^3
Convert Celsius to kelvin, which you just add 273.15. So:
37+273.15=310.15 K round to a whole number is 310 K
Sub in all numbers to calculate the mol
n= 102 x 10^3 x 2.20 x 10^3/ 8.31 x 310 (cross out 10^3 as this will make a big number)
n=102 x 2.2/8.31 x 310 =0.087 mol
We know 1 g=29 moles
Multiply 29 moles with 0.087 to find the grams
29*0.087=2.523, which to one d.p is 2.5 g
Hence, the child's lung will hold 2.5 g of air.
Hope this helps you :)
Have a nice day!!
Answer:
The mass of air is 2.53 grams
Explanation:
Step 1: Data given
Volume of the lungs = 2.20 L
Pressure = 102 kPa = 1.00666 atm
Body temperature = 37.0 °C = 310 K
Molar mass of air = 29 g/mol
Step 2: Calculate number of moles
p*V = n*R*T
⇒with p = the pressure = 1.00666 atm
⇒with V = the volume of the lungs = 2.20 L
⇒with n = the number of moles air = TO BE DETERMINED
⇒with R = the gas constant = 0.08206 L*atm/mol*K
⇒with T = the temperature = 310 K
n = (p*V)/(R*T)
n = (1.00666 * 2.20) / (0.08206* 310)
n = 0.0871 moles
Step 3: Calculate mass of air
Mass air = moles of air * molar mass
Mass air = 0.0871 moles * 29 g/mol
Mass air = 2.53 grams
The mass of air is 2.53 grams