Answer :
Answer:
a) 855.41J
b) 855.41J
Explanation:
The force equation is
N - mg - F sinθ = 0
N = mg + F sinθ
The frictonal force is =
[tex]F_x = F cos \theta[/tex]
[tex]U_xN = Fcos\theta[/tex]
substitute the value of the normal force in the above equation
[tex]U_x (mg + Fsin\theta ) = F cos\theta[/tex]
[tex]F = \frac{U_x mg}{cos\theta - U_x sin\theta } \\\\= \frac{0.41 \times 25 \times 9.8 }{cos 30^\circ- 0.41 \times sin30 ^\circ}[/tex]
= 151.96N
a) work done = F × d
= (151.96) × (6.5) cos30°
= 855.41 J
b) The increase in thermal energy of the block floor system will be equal to the work done by the worker
work done = F × d
= (151.96) × (6.5) cos30°
= 855.41 J