Answer :
Answer:
There are 10(4-legged) goats and 8(2-legged) chickens.
Step-by-step explanation:
- Let x represent the number of 4 legged goats.
- Let y represent the number of 2 legged chickens.
The total number of 4 legged goats and 2 legged chickens is 18.
Therefore: x+y=18
His son, Joseph counted 56 animal legs on the farm.
- The number of legs by x (4 legged) goats = 4x
- The number of legs by y (2 legged) Chickens = 2y
Therefore: 4x+2y=56
Solving the two equations simultaneously
x+y=18
4x+2y=56
From the first equation, x=18-y
Substitute x=18-y into the second equation
4x+2y=56
4(18-y)+2y=56
72-4y+2y=56
72-56=4y-2y
16=2y
y=8
Recall: x=18-y
x=18-8=10
x=10, y=8
There are 10(4-legged) goats and 8(2-legged) chickens.
The number of goats and chickens on the farm is 10 and 8.
Linear system
It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.
Given
The total number of 4 legged goats and 2 legged chickens is 18. His son, Joseph counted 56 animal legs on the farm.
Find the number of goats and chickens on the farm.
Let x be the goat and y be the hen.
The total number of 4 legged goats and 2 legged chickens is 18. then the equation will be
x + y = 18.....1
Joseph counted 56 animal legs on the farm. then the equation will be
4x +2y = 56.....2
On solving equations 1 and 2, we get
x = 10, and y = 8
Thus the number of goats and chickens on the farm are 10 and 8.
More about the linear system link is given below.
https://brainly.com/question/20379472