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Work the following question out on your own sheet of paper and submit a picture of your work:
A second trial is conducted for the broccoli and the following data was collected.
Initial Mass of Broccoli (g)
Final Mass of Broccoli (g)
Mass of Water (g)
16.12
14.07
75g
Initial Water Temp (°C)
20.0
Final Water Temp (°C)
32.7
Calculate the heat (energy) absorbed by the water in joules. The specific heat of water is 4.184 J/g °C.

Answer :

Neetoo

Answer:

Heat  absorbed by water = 3985.26 j

Explanation:

Given data:

Mass of water = 75 g

Initial temperature = 20.0°C

Final temperature = 32.7°C

Specific heat of water  = 4.184 j/g.°C

Heat  absorbed by water = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 32.7°C - 20°C

ΔT = 12.7 °C

Q = 75 g ×4.184 j/g.°C ×12.7 °C

Q = 3985.26 j

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