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g Certain neutron stars (extremely dense stars) are believed to be rotating at about 0.73 rev/s. If such a star has a radius of 40 km, what must be its minimum mass so that material on its surface remains in place during the rapid rotation

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Answer:

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Explanation:

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Olajidey

Answer:

the mass of the neutron stars is 2.02 × 10₂₅kg

Explanation:

The neutron stars rotate in the orbit of radius 40km

The centripetal force that acts on the neutron star is

[tex]F_c = \frac{mv^2}{r}[/tex]

The gravitational force between the neutron stars and the earth is

[tex]F_G= \frac{GMm}{r^2}[/tex]

[tex]F_G = F_c[/tex]

[tex]\frac{GMm}{r^2} = \frac{mv^2}{r} \\\\\frac{GM}{r} = v^2[/tex]

For a circular rotating object , the relation between the linear velocity and angular velocity is

[tex]v = r \omega[/tex]

substitute [tex]r\omega[/tex] for v in equation [tex]\frac{GM}{r} = v^2[/tex] ans solve for M

[tex]\frac{GM}{r} = v^2\\\\\frac{GM}{r} =(r\omega)^2\\\\M = \frac{r^3\omega^2}{G}[/tex]

angular velocity, [tex]\omega[/tex] = 0.73rev/sec = 4.587rad/sec

The distance from the neutron stars to the centre of the earth is

r = 40km = 40 × 10³m

gravitational constant, G =6.67 × 10⁻¹¹Nm²/kg²

Calculate the mass of neutron star by using the equation [tex]M = \frac{r^3\omega^2}{G}[/tex]

[tex]M = \frac{(40\times10^3)(4.587)^2}{6.67\times10^-^1^1} \\\\M = 2.02\times10^2^5kg[/tex]

Therefore, the mass of the neutron stars is 2.02 × 10₂₅kg

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