Answer :
Answer:
Current in the toroid will be [tex]I=17.32\times 10^{-3}A[/tex]
Explanation:
We have given number of winding in rectangular toroid N = 1500
Self inductance of toroid L = 0.06 H
Magnetic energy stored in toroid [tex]E=9\times 10^{-16}J[/tex]
We have to find the current in the toroid
Magnetic energy stored is equal to [tex]E=\frac{1}{2}Li^2[/tex]
[tex]9\times 10^{-6}=\frac{1}{2}\times 0.06\times I^2[/tex]
[tex]I=17.32\times 10^{-3}A[/tex]
So current in the toroid will be [tex]I=17.32\times 10^{-3}A[/tex]