Answer:
[tex]26\sqrt{3}[/tex]
Step-by-step explanation:
We want to find [tex]4\sqrt{3} +11\sqrt{12}[/tex]. [tex]11\sqrt{12}[/tex] can be written as [tex]11\sqrt{4*3}=11*\sqrt{4} *\sqrt{3}=11*2*\sqrt{3}=22\sqrt{3}[/tex], so we can now write our original equation as: [tex]4\sqrt{3}+22\sqrt{3}[/tex].
We can combine like terms: [tex]4\sqrt{3}+22\sqrt{3}=26\sqrt{3}[/tex]
Hope this helps!
Answer:
17 radical 3
Step-by-step explanation:
4(rad)3+11(rad)12
factor 12 into 13(rad)3
add 11 and 13 now that they have the same radical
keep inside rad of 3 and put 17 on the outside bc 4+13...
