Answer :
Answer:
3000
Step-by-step explanation:
The cost of interest will be given by the integral ...
[tex]\displaystyle\int\limits^{300}_{200} {(0.0006x^2-0.12x+22)} \, dx =\left.(0.0002x^3-0.06x^2+22x)\right|_{200}^{300}\\\\=6600-3600=3000[/tex]
The cost of producing units 201 through 300 is 3000.