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Mathematics

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Find limit as x approaches -3- of x/(sqrt(x^2-9)

Answer :

nobillionaireNobley nobillionaireNobley

Today at 12:15 AM

[tex]lim_{x \rightarrow -3} \frac{x}{x^2-9} =lim_{x \rightarrow -3} \frac{1}{2x} = \frac{1}{2(-3)} =- \frac{1}{6} [/tex]

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