A dance instructor chose four of his 10 students to be on stage for a performance. If order does not matter, in how many different ways can the instructor choose the four students? 10 C 4 = StartFraction 10 factorial Over (10 minus 4) factorial 4 factorial 210 1,260 6,300 25,200

Answer :

mlarsen5000

Answer:

210

Step-by-step explanation:

10x9x8x7x6x5x4x3x2x1 divided by 6x5x4x3x2x1x4x3x2x1=

(Take out 1 through 6 on both sides)

10x9x8x7 divided by 4x3x2x1=

5040 divided by 24=

210

Dance instructor can chose 4 students out of 10 if order doesn't matter in 210 ways

What is combination?

A combination is a selection of all or part of a set of objects, without regard to the order in which objects are selected.

For example, suppose we have a set of three letters: A, B, and C. We might ask how many ways we can select 2 letters from that set. Each possible selection would be an example of a combination.

Formula of combination:

[tex]C_{n} ^{r} = \frac{n!}{r! (n-r)!}[/tex]

Where

nCr is   the selection of objects from a group of objects where order of objects does not matter.

n is the total number of objects

r is the number of selected objects.

According to the question

A dance instructor chose four of his 10 students to be on stage for a performance and order does not matter .

i.e,

if we have to chose and order does not matter that means we have to use combination .

[tex]C_{n} ^{r} = \frac{n!}{r! (n-r)!}[/tex]

Total number of students (n)= 10

Number of selected students (r) = 4

[tex]C_{n} ^{r} = \frac{n!}{r! (n-r)!}[/tex]

[tex]C_{n} ^{r} = \frac{10!}{4! (6)!}[/tex]

[tex]C_{n} ^{r} = \frac{10*9*8*7}{4*3*2*1 }[/tex]

[tex]C_{n} ^{r} = \frac{5040}{24 }\\[/tex]

[tex]C_{n} ^{r} = 210[/tex]

Hence, Dance instructor can chose 4 students out of 10 in 210 ways

To know more about combination here :

https://brainly.com/question/27014146

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