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The C-train leaves Anderson Station with a velocity of 1.4 m/s and arrives at Southland Station with a velocity of 13 ms. If the train has traveled 2.5 km what was its acceleration?

Answer :

MathPhys

Answer:

0.033 m/s²

Explanation:

Given:

Δx = 2500 m

v₀ = 1.4 m/s

v = 13 m/s

Find: a

v² = v₀² + 2aΔx

(13 m/s)² = (1.4 m/s)² + 2a (2500 m)

a = 0.033 m/s²

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