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a football was kicked vertically upward from a height of 4 feet with an initial speed of 65 feet per second. the formula h=4+65t-16t^2 describes the balls height above ground, h, in feet, t seconds after it was kicked. Use the formula to find the ball's height 2 seconds after it was kicked.

Answer :

MrRoyal

Answer:

70 feet

Step-by-step explanation:

Given

[tex]h=4+65t-16t^2[/tex]

Required

Determine h when t = 2

Substitute 2 for t in the given equation

[tex]h=4+65 * 2-16* 2^2[/tex]

Solve all exponents

[tex]h=4+65 * 2-16* 4[/tex]

[tex]h=4+130-64[/tex]

[tex]h=70[/tex]

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