Answer:
29°
Step-by-step explanation:
[tex]In\: \triangle CDE\\\\
m\angle C + m\angle D + m\angle E = 180\degree \\\\
48\degree + 74\degree + m\angle E = 180\degree \\\\
122\degree + m\angle E = 180\degree \\\\
m\angle E = 180\degree- 122\degree \\\\
\huge \red {m\angle E = 58\degree} \\\\
\because \triangle ABC \cong \triangle DEC... (given) \\\\
\therefore \angle B \cong \angle E.. (CACT) \\\\
\therefore m\angle B = m\angle E\\\\
\therefore 2x = 58\degree \\\\
\therefore x =\frac{58\degree}{2}\\\\
\huge \orange {\boxed {\therefore x = 29\degree}}
[/tex]
