Answer :
Answer:
6 km/hr
Step-by-step explanation:
Let [tex]v_1[/tex] and [tex]t_1[/tex] be the average speed and the time of travel of the container ship, and [tex]v_2[/tex] and [tex]t_2[/tex] be the average speed and the time of travel of the aircraft carrier.
As the aircraft carrier left 6 hours later traveling 9 km/h faster in an effort to catch up to it and after 4 hours the aircraft carrier finally caught up.
[tex]v_2=v_1 +9[/tex]
[tex]t_2= 4[/tex] hr
and [tex]t_1-t_2=6+t_2=6+4=10[/tex] hr
As the distance covered by both is same, so
[tex]v_1t_1=v_2t_2[/tex]
[tex]\Rightarrow v_1\times 10= (v_1+9)4[/tex]
[tex]10v_1=4v_1+36[/tex]
[tex]6v_1=36[/tex]
[tex]v_1=6[/tex] km/hr
Hence, the speed of the container ship is 6 km/hr.