Answer:
Step-by-step explanation:
The vertex coordinates of f(x) = ax² + bx + c is (h, k)
where: [tex]h=\dfrac{-b}{2a}\ ,\qquad k=f(h)[/tex]
f(x) = - x² - 6x + 1 ⇒ a = -1 b = -6
So:
[tex]h=\dfrac{-(-6)}{2(-1)}=\dfrac6{-2}=-3\\\\y=f(h)=-(-3)^2-6(-3)+1=-9+18+1=10[/tex]
