Answer :
Answer:
At the elevation 617.5 feet below the sea level temperature of the water was 61\frac{1}{20}°F
Step-by-step explanation:
At 502.5 feet below the sea level temperature of the water is 63\frac{1}{4}°F
When submarine dives down 115 feet deeper, water temperature drops by 2\frac{1}{5}°F
Elevation after the submarine dove = -502.5 - 115 = -617.5 feet
This negative sign represents the elevation below the sea level.
And the temperature will be = 63\frac{1}{4}-2\frac{1}{5}
= \frac{253}{4}-\frac{11}{5}
= \frac{1265-44}{20}
= \frac{1221}{20}
= 61\frac{1}{20}°F
Therefore, at the elevation 617.5 feet below the sea level temperature of the water was 61\frac{1}{20}°F
The required expression is y = 0.01x + 58.2. Where, x = level of sea and y = temperature. At 115 feet deeper temperature is 61 1/4°F.
A submarine is exploring the Pacific Ocean. At 502.5 feet below sea level, the water temperature is 63 1/4°F.
What are functions?
It is the relationship between sets of values. e g y=f(x),
Here, assume that relation ship between temperature and sea level is linear. So the expression can be calculated as y = - 0.01x + 58.2.
Since at 115 feet deeper from 502.5 temperature-
total sea level; = 502.5+115
= 617.5
Put it in expression
y = -0.01 * 617.5 + 68.2
y = 61.25
y = 61 1/4 °F
Thus, the required expression is y = 0.01x + 58.2. Where, x = level of sea and y = temperature. At 115 feet deeper temperature is 61 1/4°F.
learn more about function here:
brainly.com/question/21145944
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