We are given:
Direction of motion: 25 degrees south of the east axis
Distance covered = 125 m
East component of the Ball:
this component is denoted by green color in the image
Once we drop a perpendicular from the end of the direction vector on the x-axis, we get a right angled triangle
The magnitude of the side of the triangle on the x-axis denotes the east component of the ball
Using trigonometry, we find that the east component of the ball is:
125 * Cos(25 degrees)
125 * 0.9 = 112.5 i (here, i denotes rightward direction on the x-axis)
North Component of the Ball:
this component is denoted by blue color in the image
Using trigonometry, we find that the North component of the ball is:
125* Sin(25 degrees) (-j) [j denotes upward movement on the y-axis, since the vector is acting downwards, we have used '-j']
125 * 0.42 (-j)
52.5 (-j) = -52.5 j
Therefore the direction vector of the ball is 112.5 i - 52.5 j
where 112.5 i is the East Component and -52.5 is the North Component
