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Carol pushes down at an angle of 30 degrees from the vertical on a 10.0 kg wood crate causing the crate to move across a wood floor at a constant velocity of 2.0 m/s. How much force does Carol exert on the crate? (μs = 0.5 and μk = 0.2)

Answer :

hamzaahmeds

Answer:

F = 39.2 N

Explanation:

Since, the object is in uniform motion. Therefore, the frictional force on object will be:

Frictional Force = μk N = μk mg

where,

μk = coefficient of kinetic friction = 0.2

m = mass of crate = 10 kg

g = 9.8 m/s²

Therefore,

Frictional Force = (0.2)(10 kg)(9.8 m/s²)

Frictional Force = 19.6 N

The horizontal component of force must be equal to this frictional force to continue the uniform motion:

F Sin 30° = 19.6 N

F = 19.6 N/Sin 30°

F = 39.2 N

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