kelpM3
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HURRY GETTING TIMED Which values are two of the possible solutions to the equation?

Which values are two of the possible solutions to the equation?

Sine (5 x minus pi) = StartFraction StartRoot 2 EndRoot Over 2 EndFraction, 0 less-than-or-equal-to x less-than 2 pi

Left-brace StartFraction pi Over 20 EndFraction, StartFraction 3 pi Over 20 EndFraction right-brace
Left-brace StartFraction pi Over 4 EndFraction, StartFraction 7 pi Over 4 EndFraction right-brace
Left-brace StartFraction pi Over 4 EndFraction, StartFraction 7 pi Over 20 EndFraction right-brace
Left-brace StartFraction 5 pi Over 4 EndFraction, StartFraction 7 pi Over 4 EndFraction right-brace

HURRY GETTING TIMED Which values are two of the possible solutions to the equation? Which values are two of the possible solutions to the equation? Sine (5 x mi class=

Answer :

The possible values of the solutions to the equations are; (π/4, 7π/4)

How to solve trigonometric equations?

We are given the equation;

sin(5x - π) = (√2)/2

Now, (√2)/2 is also expressed as 1/√2.

Thus;

sin(5x - π) = 1/√2

5x - π = sin⁻¹(1/√2)

5x - π = π/4

5x = π + π/4

5x = ⁵/₄π

Thus;

x = π/4

Now, since x < 2π, then it means it is in the fourth quadrant. Thus;

x = 7π/4

Read more about Trigonometric Equations; https://brainly.com/question/1687218

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tomchen882

Answer:

prob d

Step-by-step explanation:

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