Answer:
The point-slope form of the equation of the perpendicular line that goes through (5, 0) is:
- [tex]y=-\frac{1}{2}x+\:\frac{5}{2}[/tex]
Step-by-step explanation:
Given the equation
[tex]y=2x-1[/tex]
comparing the equation with the slope-intercept form
[tex]y=mx+b[/tex]
Here,
so the slope of the line is 2.
As we know that the slope of the perpendicular line is basically the negative reciprocal of the slope of the line, so
The slope of the perpendicular line will be: -1/2
Therefore, the point-slope form of the equation of the perpendicular line that goes through (5, 0) is:
[tex]y-y_1=m\left(x-x_1\right)[/tex]
[tex]y-0=\frac{-1}{2}\left(x-5\right)[/tex]
[tex]y=\frac{-1}{2}\left(x-5\right)[/tex]
[tex]\:y=-\frac{1}{2}x+5\cdot \:\frac{1}{2}[/tex]
[tex]y=-\frac{1}{2}x+\:\frac{5}{2}[/tex]
