Answer:
The equation in the slope-intercept form will be:
[tex]y=6x-3[/tex]
Step-by-step explanation:
Given
As we know that the equation of a line in point-slope form is
[tex]y-y_1=m\left(x-x_1\right)[/tex]
substituting the values m = 6 and point = (1, 3)
[tex]y-3=6\left(x-1\right)[/tex]
Writing the equation in slope-intercept form
[tex]y=mx+b[/tex]
where m is the slope, and b is the y-intercept
so the equation of the line in slope-intercept form becomes
[tex]y-3=6\left(x-1\right)[/tex]
add 3 to both sides
[tex]y-3+3=6\left(x-1\right)+3[/tex]
[tex]y=6x-3[/tex]
Therefore, the equation in the slope-intercept form will be:
[tex]y=6x-3[/tex]
