Answer :
Answer:
[tex]11[/tex]
Step-by-step explanation:
Method A
[tex](3*\pi )*11\approx103.62[/tex]
[tex](4*\pi )*11\approx138.16[/tex]
[tex]138.16-103.62=34.54[/tex]
[tex]34.54\div\pi\approx11[/tex]
Method B
[tex]3\pi*11=33\pi[/tex]
[tex]4\pi*11=44\pi[/tex]
[tex]44\pi-33\pi=11\pi[/tex]
Volume is a three-dimensional scalar quantity. The volume of extra water that the new pipe can hold is 77π cm³.
What is volume?
A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
Given the radius and the height of old pipe is 3cm and 11 cm respectively. Therefore, the volume of water that old pipe can handle is,
Volume of water = πr²h = π × (3cm)² × 11 cm = 99π cm³
Also, given the radius and the height of new pipe is 4cm and 11 cm respectively. Therefore, the volume of water that new pipe can handle is,
Volume of water = πr²h = π × (4cm)² × 11 cm = 176π cm³
Now, the volume of extra water that the new pipe can hold is,
Extra volume carried by new pipe = 176π cm³ - 99π cm³
= 77π cm³
Hence, the volume of extra water that the new pipe can hold is 77π cm³.
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