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What is the equation in point-slope form of a line that passes through the points (5, −3)(5, −3) and (−2, 9)(−2, 9) ?
y−3=−2(x+5

y+3=−127(x−5)

y+3=−2(x−5)

y−3=−127(x+5)

Answer :

apologiabiology
point sloe is
y-y1=m(x-x1)
slope=m
a ponint is (x1,y1)

slope=(y2-y1)/(x2-x1)
(x,y)
(5,-3)
(-2,9)
slope=(9-(-3))/(-2-5)=12/-7=-12/7
m=-12/7

a point is (5,-3)
x1=5
y=-3
y-(-3)=-12/7(x-5)
y+3=-12/7(x-5)

2nd one

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