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For the following right triangle, find the side length x. Round your answer to the nearest hundredth.
11
10
Х

PLZ HELP ME For the following right triangle, find the side length x. Round your answer to the nearest hundredth. 11 10 Х class=

Answer :

Answer:

x ≈ 14.87

Step-by-step explanation:

Using Pythagoras' identity in the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is

x² = 10² + 11² = 100 + 121 = 221 ( take the square root of both sides )

x = [tex]\sqrt{221}[/tex] ≈ 14.87 ( to the nearest hundredth )

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