Answer:
C - He substituted incorrectly when calculating the constant of variation.
The first error, in Nick’s work is given inn option C, i.e. He substituted incorrectly when calculating the constant of variation.
Constant of variation is the ratio between two variables in a direct variation or the product of two variables in an inverse variation.
We have,
s = 4, and t = 12
Now according to the question,
The variable s varies directly as the square of t,
i.e.
s = kt²
So,
Substituting given values of s and t,
s = kt²
i.e.
4 = k × 12²
⇒
[tex]k = \frac{4}{144}=\frac{1}{36}[/tex],
Now,
for 48,
i.e.
s = kt²,
We get,
[tex]48 = \frac{1}{36} t^2[/tex],
i.e.
[tex]t^2=36 *48=1728[/tex]
[tex]t=\sqrt{1728} = \sqrt{3*576} =24\sqrt{3}[/tex]
So, this is the correct value for t.
Hence, we can say that the first error, in Nick’s work is given inn option C, i.e. He substituted incorrectly when calculating the constant of variation.
To know more about constant of variation click here
https://brainly.com/question/14254277
#SPJ2