Answer :

Space

Answer:

166 g HCl

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Chemistry

Stoichiometry

  • Reading a Periodic Table
  • Balancing Equations
  • Using Dimensional Analysis

Explanation:

Step 1: Define

[RxN - Unbalanced] Mg (s) + HCl (aq) → MgCl₂ (aq) + H₂ (g)

[RxN - Balanced] Mg (s) + 2HCl (aq) → MgCl₂ (aq) + H₂ (g)

[Given] 2.28 mol Mg (s)

Step 2: Identify Conversions

[RxN] 1 mol Mg = 2 mol HCl

Molar Mass of H - 1.01 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of HCl - 1.01 + 35.45 = 36.46 g/mol

Step 3: Stoichiometry

  1. Set up:                               [tex]\displaystyle 2.28 \ mol \ Mg(\frac{2 \ mol \ HCl}{1 \ mol \ Mg})(\frac{36.46 \ g \ HCl}{1 \ mol \ HCl})[/tex]
  2. Multiply:                             [tex]\displaystyle 166.258 \ g \ HCl[/tex]

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

166.258 g HCl ≈ 166 g HCl

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